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Bob’s velocity is given by \(B(t)=t^3-6t^2+300\) meters per minute on \(0\le t\le 10\); acceleration is the derivative of velocity, so the video evaluates \(B'(5)\) and gets 15 meters per minute squared. The walkthrou...
Unknown · 0:00
Bob’s velocity is given by \(B(t)=t^3-6t^2+300\) meters per minute on \(0\le t\le 10\); acceleration is the derivative of velocity, so the video evaluates \(B'(5)\) and gets 15 meters per minute squared. The walkthrou...
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